Array-2 > bigDiff

Given an array length 1 or more of ints, return the difference between the largest and smallest values in the array. Note: the built-in Math.min(v1, v2) and Math.max(v1, v2) methods return the smaller or larger of two values.

public class bigDiff {

    public static void main(String[] args) {

        int[] nums ={2, 10, 7, 2};

        //min and max value of array
        int min = Integer.MAX_VALUE;
        int max = Integer.MIN_VALUE;

// for each loop 

        for (int minInt: nums) {
            if(minInt<min){
                min=minInt;
            }
        }System.out.println(min);

        // max value of array
        for (int maxInt: nums) {
            if(maxInt>max){
                max=maxInt;
            }
        }System.out.println(max);

        System.out.println(max-min);


    }
}

or

    public static void main(String[] args) {
        int[] nums ={10, 3, 5, 6};

        int min = nums[0];
        int max = nums[0];

        for (int i = 0 ; i < nums.length-1; i++)
        {
            min = Math.min(nums[i],min);
            max = Math.max(nums[i],max);
        }
        System.out.println(max-min);

    }